Question 47: A balance plate balances when: On the left weighing pan there are 2 packages of candy, on the right weighing plate there are weights of 100g, 50g, 20g, 20g and 10g. On the left weighing plate, there are 5 packages of candy, on the right plate there are 2 packages of powdered milk. Determine the mass of 1 pack of candy m1 , 1 pack of milk powder m2 . Given that the candy packs have the same weight, the milk powder packets have the same mass.

+ Because the balance is in balance, the mass of the object to be measured on the left is equal to the sum of the masses of the weights on the right.

+ The weight of 2 packs of candy on the left is: \(m = 100 + 50 + 20 + 20 + 10 = 200g.\)

+ Calculate the mass of 1 pack of candy is: \(m_1 = m : 2 = 200 : 2 = 100g.\)

+ The mass of 5 packs of candy on the left is equal to the volume of 2 packs of powdered milk on the right.

+ Weight of a pack of powdered milk: \(5,100=2,m_{suabot} \to m_{suabot}=250g\)