Question 8: Given the number \(a{\text{ }} = {\text{ }}{9^{11}}\; + {\text{ }}1\).The number a is:

A. Divisible by 5 but not divisible by 2.

B. Divisible by both 2 and 5.

C. Not divisible by 5.

D. Divisible by 2 but not divisible by 5.

We have: a = 9¹¹ + 1 = (9.9).(9.9).(9.9).(9.9).(9.9).9 + 1 = 815.9 + 1 = ….1.9 + 1 ends in 0, so a is divisible by both and 5.

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