Question 1: Find the natural numbers n satisfying 6 (n + 1)

A. n ∈{0; first; 2; 5}

B. n ∈{0; 2; 3; 6}

C. n ∈{0; 6; twelfth; 18; …}

D. n ∈ {0; 5; 11; 17; …}

Because \(6 \vdots (n + 1)\) so n + 1 belongs to U(6).

Divide 6 by the natural numbers from 1 to 6, we see that 6 is divisible by 1; 2; 3; 6.

Then U(6) = {1; 2; 3; 6}.

It follows that n + 1 belongs to {1; 2; 3; 6}.

Or n belongs to {0; first; 2; 5}.

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