Question 1: A natural number with two digits, the digits are the same, if the number is divisible by 2 and divided by 5, the remainder 3:

A number that is divisible by 2 has its last digit 0; 2; 4; 6; 8

A number that has a remainder of 3 when divided by 5 has a digit ending in 3 or 8

So a number that is divisible by 2 and divided by 5 leaves a remainder of 3 whose last digit is 8 .

But the number to find has two digits, the digits are the same, so the number is 88